Trigonometry

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360º = 2π radians

180º = π radians

90º = \frac {\pi}{2} radians

60º = \frac {\pi}{3} radians

45º = \frac {\pi}{4} radians

30º = \frac {\pi}{6} radians


Arc length, l = rθ

Area of sector = ½r²θ


Tanθ = \frac {sin \theta}{Cos \theta}

Sin²θ + cos²θ = 1

1 + cot²θ = cosec²θ

cotθ =  \frac {cos \theta}{sin \theta}

1 + tan²θ = sec²θ


sin (-θ) = -sinθ

cos(-θ) = cosθ

tan(-θ) = -tanθ


tan(A+B) = \frac {tanA + tanB}{1 - tanAtanB}

tan(A-B) = \frac {tanA - tan B}{1 + tanAtanB}


sin(A+B) = sinAcosB + cosAsinB

sin(A-B) = sinAcosB – cosAsinB

cos(A+B) = cosAcosB – sinAsinB

cos(A-B) = cosAcosB +sinAsinB


2sinAcosB = sin(A+B) + sin(A-B)

2cosAsinB = sin(A+B) – sin(A-B)

2cosAcosB = cos(A+B) + cos(A-B)

2sinAsinB = cos(A-B) – cos(A+B)


cos2A = cos²A – sin²A

cos2A = 2cos²A – 1

cos2A = 1 – 2sin²A

sin2A = 2sinAcosA

tan2A = \frac {2tanA}{1-tan^2A}


sin3A =3sinA – 4sin³A


cos²A = ½(1 + cos2A)

sin²A = ½(1 – cos2A)


If 2cos3Asin2A = 0

Then cos3A=0 sin2A=0

Who Added These Notes?

Amp

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